scanf("%f %d %d %[abcdefghijklmnopqrstuvwxyz] %*ld %s%n",&fp1,&i,&j,word1,word2,&byte_count);

Question

int main()
{
	int value_count = 0;
	float fp1 = 0.0;
	int i =0;
	int j =0;
	char word1[SIZE]=" ";
	char word2[SIZE]=" ";
	int byte_count = 0;

	value_count = scanf("%f %d %d %[abcdefghijklmnopqrstuvwxyz] %*ld %s%n",&fp1,&i,&j,word1,word2,&byte_count); //代码这一句看不懂请前辈指点，谢谢。
	printf("nCount of bytes read = %dn",byte_count);
	printf("nfp1 = %f i = %d j=%d",fp1,i,j);
	printf("nword1 = %s word2 = %sn",word1,word2);
	return 0;
}

Answer 1

大家是不是都放假了？？没人回复？？？