请教关于APACHE的进程
为什么我按装的php+apache+informix 在正常启动apache 后.我的Linux系统的进程会出现如下情况:
root 3649 1 0 09:27 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 3650 3649 0 09:27 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 3651 3649 0 09:27 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 3652 3649 0 09:27 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 3653 3649 0 09:27 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 3654 3649 0 09:27 ? 00:00:00 /usr/local/apache/bin/httpd -k start
bit 3655 3650 0 09:27 ? 00:00:00 [sqlexec <defunct>;]
nobody 3656 3649 0 09:27 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 4417 3649 0 14:40 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 4418 3649 0 14:40 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 4419 3649 0 14:40 ? 00:00:00 /usr/local/apache/bin/httpd -k start
nobody 4420 3649 0 14:40 ? 00:00:00 /usr/local/apache/bin/httpd -k start
bit 4421 3650 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4422 3652 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4423 3651 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4424 3653 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4425 3654 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4426 3656 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4427 3650 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4428 3652 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4429 3651 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4430 3653 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4431 3654 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4432 3656 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4433 3652 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4434 3650 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4435 3653 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4436 3651 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4437 3654 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4438 3656 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4439 3652 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
bit 4440 3650 0 14:40 ? 00:00:00 [sqlexec <defunct>;]
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