Python 判断 数的大小

Question

8.92307731084
<type 'float'>
8.30005007762
<type 'float'>
17.6684817549
<type 'float'>
19.8371142027
<type 'float'>]

我怎么能获取到这里面的最小数值或者最大数值呢?

求大侠们帮忙解释下~

Answer 1

好~谢谢

Answer 2

这个我知道 - -! 不过 谢谢~ 呵呵

Answer 3

[root@renwofei vm]# python
Python 2.6.6 (r266:84292, Sep 12 2011, 14:03:14) 
[GCC 4.4.5 20110214 (Red Hat 4.4.5-6)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> a=8.92307731084
>>> b=8.30005007762
>>> a
8.9230773108400001
>>> b
8.3000500776199999
>>> if a >b :
...     print "a>b"
... else:
...     print "a<b"
... 
a>b
>>> 

Answer 4

我没用过这样的函数!我做到是参数化设计的~ 所有 可不可以写一段完整的简短的代码 我看看~

Answer 5

build-in function max() and min()

Answer 6

可以

Answer 7

list_a = [8.92307731084, 8.30005007762, 17.6684817549]

max_a = max(list_a)