两个接口返回的数据拼接到一张表中

Question

两个接口返回的数据结构是一样的，我怎么把第二个接口返回的数据拼接在第一个生成的表的下面呢？

Answer 1

我理解你是想把了两个接口的返回结果进行一个合并？
伪代码:

async function getData() {
 let data1 = await get1();
 let data2 = await get2();
 data1 = [...data1, ...data2]// 或者{...data1, ...data2}
}

Answer 2

因为你的数据具体什么结构没有讲，所以没法讲具体的如何合并，但是对于数据合并其实就是判断数据类型再进行拼接，具体的可以网上搜下merge，比如这个https://www.jianshu.com/p/795...

jq中也有类似实现，比如jQuery.merge 和 jQuery.extend，下面是jQuery.extend代码，可以借鉴下

jQuery.extend = jQuery.fn.extend = function() {
    var src, copyIsArray, copy, name, options, clone,
        target = arguments[0] || {},
        i = 1,
        length = arguments.length,
        deep = false;

    // Handle a deep copy situation
    if ( typeof target === "boolean" ) {
        deep = target;

        // skip the boolean and the target
        target = arguments[ i ] || {};
        i++;
    }

    // Handle case when target is a string or something (possible in deep copy)
    if ( typeof target !== "object" && !jQuery.isFunction(target) ) {
        target = {};
    }

    // extend jQuery itself if only one argument is passed
    if ( i === length ) {
        target = this;
        i--;
    }

    for ( ; i < length; i++ ) {
        // Only deal with non-null/undefined values
        if ( (options = arguments[ i ]) != null ) {
            // Extend the base object
            for ( name in options ) {
                src = target[ name ];
                copy = options[ name ];

                // Prevent never-ending loop
                if ( target === copy ) {
                    continue;
                }

                // Recurse if we're merging plain objects or arrays
                if ( deep && copy && ( jQuery.isPlainObject(copy) || (copyIsArray = jQuery.isArray(copy)) ) ) {
                    if ( copyIsArray ) {
                        copyIsArray = false;
                        clone = src && jQuery.isArray(src) ? src : [];

                    } else {
                        clone = src && jQuery.isPlainObject(src) ? src : {};
                    }

                    // Never move original objects, clone them
                    target[ name ] = jQuery.extend( deep, clone, copy );

                // Don't bring in undefined values
                } else if ( copy !== undefined ) {
                    target[ name ] = copy;
                }
            }
        }
    }

    // Return the modified object
    return target;
};