js/es6 两个数组过滤字段并对应上值

Question

原数据格式↓

const formInit = {
  id: '',
  name: '',
  type: ''
}

const data = {
  id: '123',
  name: '你好',
  type: '1',
  updateTime: '2021-6-9',
  updateBy: 'admin'
}

期待结果↓

const result = {
  id: '123',
  name: '你好',
  type: '1'
}

就是我需要的是formInit的字段和相对应data的字段及value，像updateTime和updateBy这种formInit里面没有的字段就不要。
求大神们给个简便的方法

感谢各位大哥大姐的解答，小弟感激不尽！

Answer 1

const build = (init, data) => {
  let keys = Object.keys(init);
  return Object.fromEntries(
    Object.entries(data).filter(([key]) => keys.includes(key))
  );
};

Answer 2

用结构赋值就行了
{id,type,name}=data
formInit={id,type,name}
就行了

Answer 3

var formInit = {
        id: '',
        name: '',
        type: ''
    };

    var data = {
        id: '123',
        name: '你好',
        type: '1',
        updateTime: '2021-6-9',
        updateBy: 'admin'
    };
    Object.keys(formInit).forEach((key) => formInit[key] = data[key]);
    console.log(JSON.stringify(formInit));
//{"id":"123","name":"你好","type":"1"}