CompletableFuture allOf 之后参数问题？

Question

CompletableFuture<String> n1PromQuery = CompletableFuture.supplyAsync(() -> {
    String storeArea = null;
 for (AllowQtyApply allowQtyApply : pageResult.getList()) {
        if(storeArea == null) {
            storeArea = allowQtyApply.getStoreArea();
 }
    }
    String n1Prom = null;
 ......
    return n1Prom;
});

CompletableFuture<List<String>> itemNosQuery = CompletableFuture.supplyAsync(() -> {
    List<String> itemNos = new ArrayList<>();
 for (AllowQtyApply allowQtyApply : pageResult.getList()) {
        itemNos.add(allowQtyApply.getItemNo().toString());
 }
    return itemNos;
});

CompletableFuture<Void> n1PromItemNos = CompletableFuture.allOf(n1PromQuery, itemNosQuery);
CompletableFuture<Map<String, Map<String,String>>> n1PromMapQuery  = n1PromItemNos.thenApplyAsync((n1Prom, itemNos) -> {
    Map<String, Map<String,String>> n1Map = new HashMap<>();
 List promNoList = new ArrayList();
 Map<String, String> n1PromMap = new HashMap<String, String>();
 Map<String, String> n1PromClassMap = new HashMap<String, String>();
 if (n1Prom != null && (List)itemNos.size() > 0) {
        promNoList.add(n1Prom);
 CSEResponse cseResponse = ProdCenterClient.getPromStoreProducts(storeNo, promNoList, itemNos);//
 ............................
});

新学CompletableFuture 不太理解, 我以为我allOf 组合了 前两个CompletableFuture之后的新的CompletableFuture可以直接使用前两个的返回值作为参数，但是实际这样做是报错的，如果我想组合后使用前两个的返回值作为参数应该怎么写 ？？

Answer 1

和js的Promise.all不同，java的allof后的新的CompletableFuture并无法获取前面的结果作为参数，但可以这样取值：

CompletableFuture.allOf(n1PromQuery, itemNosQuery).thenApplyAsync(() -> {
  //获取前两个的结果
  String n1Prom = n1PromQuery.join();//虽然用join,但执行到这一步之前必定已经执行完成了，所以这里是不会阻塞的
  List<String> itemNos = itemNosQuery.join();//同上
  .....
});