sed 命令删除指定行

Question

record 文件里有以下数据

1607583364561;/app/rm/a.x;./a.x;1210145604
1607583364561;/app/rm/b.x;./b.x;1210145604
1607583364561;/app/rm/c.x;./c.x;1210145604
1607583364561;/app/rm/d.x;./d.x;1210145604
1607587139072;/app/rm/a.b;a.b;20201210155859
1607587139072;/app/rm/a.c;a.c;20201210155859
1607587139072;/app/rm/a.d;a.d;20201210155859
1607587139072;/app/rm/a.e;a.e;20201210155859

我需要删除其中一行

sed "/1607587139072;/app/rm/a.b;a.b;20201210155859/d" /record

结果返回
1607583364561;/app/rm/a.x;./a.x;1210145604
pp/rm/a.x;./a.x;1210145604/p
1607583364561;/app/rm/b.x;./b.x;1210145604
pp/rm/a.x;./a.x;1210145604/p
1607583364561;/app/rm/c.x;./c.x;1210145604
pp/rm/a.x;./a.x;1210145604/p
1607583364561;/app/rm/d.x;./d.x;1210145604
pp/rm/a.x;./a.x;1210145604/p
1607587139072;/app/rm/a.b;a.b;20201210155859
1607587139072;/app/rm/a.c;a.c;20201210155859
1607587139072;/app/rm/a.d;a.d;20201210155859
1607587139072;/app/rm/a.e;a.e;20201210155859

我想可能是正则表达式中带有/，添加转译后

sed '/1607587139072;\/app\/rm\/a\.b;a\.b;20201210155859/p' /tmp/recycle/.record
1607583364561;/app/rm/a.x;./a.x;1210145604
1607583364561;/app/rm/b.x;./b.x;1210145604
1607583364561;/app/rm/c.x;./c.x;1210145604
1607583364561;/app/rm/d.x;./d.x;1210145604
1607587139072;/app/rm/a.b;a.b;20201210155859
1607587139072;/app/rm/a.b;a.b;20201210155859
1607587139072;/app/rm/a.c;a.c;20201210155859
1607587139072;/app/rm/a.d;a.d;20201210155859
1607587139072;/app/rm/a.e;a.e;20201210155859

全部都被输出了，请问我想删除指定的任意一行应该怎么做？

Answer 1

我试了转译后可以删掉啊？

Answer 2

sed -i 'Nd' filename N为行数