【已解决】如何将2个list里面的dict按顺序合并

Question

有2个list，里面都了数量相同的dict

a = [{"name":"aaa", "id":"123"}, {}, {}...]
b = [{"age":"18"}, {}, {}...]

我想把b_list的dict 合并到a_list的dict 里面。
变成：

c = [{"name":"aaa", "id":"123", "age":"18"}, {}, {}...]

但是需要按顺序的合并。
像这样

a = [{"name":"aaa", "id":"001"}, 
     {"name":"bbb", "id":"002"},
     {"name":"ccc", "id":"003"},
     {"name":"ddd", "id":"004"}]

b = [{"age":"18"},
     {"age":"19"},
     {"age":"20"},
     {"age":"21"}]

# 预期的结果
c = [{"name":"aaa", "id":"001", "age":"18"}, 
     {"name":"bbb", "id":"002", "age":"19"},
     {"name":"ccc", "id":"003", "age":"20"},
     {"name":"ddd", "id":"004", "age":"21"}]

解决了！！
感谢网友Paradise的回答

for i, j in zip(a, b):
    i.update(j)
    c.append(i)