如何在 shell 脚本中修改配置文件？取消某些注释 / 修改些值什么的？

Question

我在 CentOS 下，想要编写一个 Shell 脚本修改 Nginx 的配置文件 nginx.conf，做如下修改：

1、取消下面行的程序注释

# pass the PHP scripts to FastCGI server listening on 127.0.0.1:9000
#
#location ~ .php$ {
#    root           html;
#    fastcgi_pass   127.0.0.1:9000;
#    fastcgi_index  index.php;
#    fastcgi_param  SCRIPT_FILENAME  /scripts$fastcgi_script_name;
#    include        fastcgi_params;
#}

2、把其中的

fastcgi_param  SCRIPT_FILENAME  /scripts$fastcgi_script_name;

修改为

fastcgi_param  SCRIPT_FILENAME  $document_root$fastcgi_script_name;

请问如何在 Shell 脚本中通过编程实现？谢谢！

Answer 1

谢谢！能稍微解释一下么？看不太懂，呵呵。

Answer 2

就是在含有 .php$ 字符的一行前面插入一段内容

Answer 3

哦，我知道了！谢谢！

Answer 4

sed '/.php$/i location ~ .php$ {n    root           html;n    fastcgi_pass   127.0.0.1:9000;n    fastcgi_index  index.php;n    fastcgi_param  SCRIPT_FILENAME  $document_root$fastcgi_script_name;n    include        fastcgi_params;n}' nginx.conf

 

opadmin@discuz:~/temp$ sed '/.php$/i location ~ .php$ {n    root           html;n    fastcgi_pass   127.0.0.1:9000;n    fastcgi_index  index.php;n    fastcgi_param  SCRIPT_FILENAME  $document_root$fastcgi_script_name;n    include        fastcgi_params;n}' aaa.txt

# pass the PHP scripts to FastCGI server listening on 127.0.0.1:9000
#
location ~ .php$ {
    root           html;
    fastcgi_pass   127.0.0.1:9000;
    fastcgi_index  index.php;
    fastcgi_param  SCRIPT_FILENAME  $document_root$fastcgi_script_name;
    include        fastcgi_params;
}
#location ~ .php$ {
#    root           html;
#    fastcgi_pass   127.0.0.1:9000;
#    fastcgi_index  index.php;
#    fastcgi_param  SCRIPT_FILENAME  /scripts$fastcgi_script_name;
#    include        fastcgi_params;
#}