php通过前端传来的值作为 数据库表名查询数据 并且再返回所有数据给前端?

Question

php 代码

<?php
header("Access-Control-Allow-Origin: *");
header("Content-type:text/html;charset=utf-8");
$url = "mysql: host=localhost;dbname=testing";
$user = "root";
$pwd = "0123456zp";
$conn=new PDO($url,$user,$pwd);
$conn->query("set names utf8");

$name=$_GET["name"];//姓名

$sql = "select * from $name";
$rst = $conn->query($sql);
$result=$rst->fetchAll();

echo json_encode($result,JSON_UNESCAPED_UNICODE);

前端代码

 $.ajax({
        url: "../action/s.php",
        type: "get",
        data:{"id":names},
        success: function (res) {
            var data = jQuery.parseJSON(res);

        }
        });

求前辈指点 给修改一下怎么实现 谢谢