GUN parallel并行执行shell函数

Question

#!/bin/bash

dir=/root/
code_dir="code"
doubleit() 
{
    local transfer_dir=$1
    local moudles=`cat ${code_dir}/depend/$2`

    for module in $ moudles;do
        ${code_dir}/build/build_module.sh $transfer_dir $module
        transfer $transfer_dir
    done
}


export -f doubleit
export -f transfer

export code_dir

parallel doubleit ::: $dir ::: base basis

实际项目中使用大致上面代码，有很多基础模块，分为两类，一类是c/c++使用，一类是nginx 和php的，因此两类模块间没有依赖我想实现并行编译打包。但是每一类模块间要按照文件中的顺序进行编译。
但是按照上面写法后，提示job failed,我手动去运行提示失败的job确发现没有问题，echo $?是0，parallel是如何判断job failed?
出错信息：（都是些告警，实际项目中的信息，可能参考意义不大，可以从哪些方面排查）

Makefile:18: warning: overriding recipe for target `install'
common.mk:100: warning: ignoring old recipe for target `install'
upgrade_col.cpp: In function ‘void increase_update_count(unsigned int)’:
upgrade_col.cpp:170:33: warning: narrowing conversion of ‘uptime’ from ‘time_t {aka long int}’ to ‘unsigned int’ inside { } is ill-formed in C++11 [-Wnarrowing]
   update_ctx_t uctx = {1, uptime};
                                 ^
Makefile:18: warning: overriding recipe for target `install'
common.mk:100: warning: ignoring old recipe for target `install'
parallel: This job failed:
build_packages_parallel /root/v2.5/code/build/eps_cloud basis

Answer 1

parallel看不到bash函数. 你得写成单独文件.