Python PIL库,我在一张固定大小的图片上写字,怎么实现文字超过到底自动换行?

Question

字体固定,字体大小固定,有中文英文标点符号
求高手指点,谢谢.

Answer 1

依赖

• C:WindowsFontsmicross.ttf
• PILLOW

from PIL import Image, ImageDraw, ImageFont


class ImgText:
    font = ImageFont.truetype("micross.ttf", 24)

    def __init__(self, text):
        # 预设宽度 可以修改成你需要的图片宽度
        self.width = 100
        # 文本
        self.text = text
        # 段落 , 行数, 行高
        self.duanluo, self.note_height, self.line_height = self.split_text()

    def get_duanluo(self, text):
        txt = Image.new('RGBA', (100, 100), (255, 255, 255, 0))
        draw = ImageDraw.Draw(txt)
        # 所有文字的段落
        duanluo = ""
        # 宽度总和
        sum_width = 0
        # 几行
        line_count = 1
        # 行高
        line_height = 0
        for char in text:
            width, height = draw.textsize(char, ImgText.font)
            sum_width += width
            if sum_width > self.width:  # 超过预设宽度就修改段落 以及当前行数
                line_count += 1
                sum_width = 0
                duanluo += '\n'
            duanluo += char
            line_height = max(height, line_height)
        if not duanluo.endswith('\n'):
            duanluo += '\n'
        return duanluo, line_height, line_count

    def split_text(self):
        # 按规定宽度分组
        max_line_height, total_lines = 0, 0
        allText = []
        for text in self.text.split('\n'):
            duanluo, line_height, line_count = self.get_duanluo(text)
            max_line_height = max(line_height, max_line_height)
            total_lines += line_count
            allText.append((duanluo, line_count))
        line_height = max_line_height
        total_height = total_lines * line_height
        return allText, total_height, line_height

    def draw_text(self):
        """
        绘图以及文字
        :return:
        """
        note_img = Image.open("001.png").convert("RGBA")
        draw = ImageDraw.Draw(note_img)
        # 左上角开始
        x, y = 0, 0
        for duanluo, line_count in self.duanluo:
            draw.text((x, y), duanluo, fill=(255, 0, 0), font=ImgText.font)
            y += self.line_height * line_count
        note_img.save("result.png")


if __name__ == '__main__':
    n = ImgText(
        "1234567890" * 5)
    n.draw_text()

效果

原始图

成果图