easyUI提交表单报错

Question

报错如下：

代码如下：

$('#addForm').form('submit', {
                url: "warm_car_customer_invite_friend_create",
                onSubmit: function () {
                    alert("erefge");
                    $.messager.progress({
                        text: "正在加载，请稍等！"
                    });
                    var flag = $(this).form("validate");
                    if (!flag) {
                        $.messager.progress('close');
                    }
                    return flag;
                },
                success: function (result) {
                    $.messager.progress('close');
                    if (result == "success") {
                        $.messager.alert("提示", "保存成功", "info");
                        $("#dataGrid").datagrid("reload");
                        $("#addForm").form('clear');
                        $("#addView").dialog("close");
                    } else {
                        $.messager.alert("提示", "保存失败", "info");
                        $("#dataGrid").datagrid("reload");
                        $("#addView").dialog("close");
                    }
                }
            });

Answer 1

是html中的form元素写成from了...