koa ,post,改成delete怎么接收参数，如下图和代码

Question

post

// router.post('/userDel', async (ctx, next) => {
//     let id = ctx.request.body.id;
//     await userModel.deleteUserData(id)
//         .then(result => {
//             ctx.body = {
//                 data: result,
//                 state: 200
//             }
//         })
//         .catch(error => {
//             console.log(error)
//         })
// });

delete

router.delete('/userDel', async (ctx, next) => {
    let id = ctx.request.body.id;
    await userModel.deleteUserData(id)
        .then(result => {
            ctx.body = {
                data: result,
                state: 200
            }
        })
        .catch(error => {
            console.log(error)
        })
});

Answer 1

delete请求一般不需要请求体，直接将参数体现在url上就可以了。https://developer.mozilla.org...
如：
/userDel?id=userid

router.delete('/userDel', async (ctx, next) => {
    // url的query参数获取
    const id = ctx.request.query.id;
});

或者
/userDel/userid

router.delete('/userDel/:id', async (ctx, next) => {
    // url的路径参数
    const id = ctx.params.id;
});