swift的uiview点击事件怎么传参数?

Question

swift的按钮点击事件怎么传参数呢？找了好久没找到，下面是我的写法，但是报错。大神稍微指导下

 let btn = UIButton.init(frame: CGRect(x:100,y:500,width:200,height:30))
            btn.backgroundColor  = UIColor.black
            
            btn.addTarget(self, action: #selector(test(title:)), for: .touchUpInside)
            view.addSubview(btn)
            
    @objc func test(title:String){
        
        print(title)
        
    }

Answer 1

阅读量还是挺高的，看来不少人遇到了这个问题；我也是在寻找 UIView 点击事件的参数传递；目前我通过 tag 解决了

UIButton 的点击参数传递

设置 UIButton 的 tag，详细见代码

let playButton = UIButton(type: .custom)
playButton.setTitle("开始播放", for: .normal)
playButton.backgroundColor = UIColor(white: 1.0, alpha: 0.8)
playButton.layer.cornerRadius = 17.5
playButton.tag = index // 关键在这一行
playButton.addTarget(self, action: #selector(playClicked(button:)), for: .touchUpInside)
itemView.addSubview(playButton)

接收

@objc func playClicked(button: UIButton){
    print(button.tag)
}

UIView 的点击事件与传输传递

UIView 是没有点击事件这个东西的，不过我们可以用 UITapGestureRecognizer 手势来解决

详细见代码

let itemView = UIView()
itemView.isUserInteractionEnabled = true

itemView.tag = index  // 传输传递

// 创建手势
let tap = UITapGestureRecognizer(target: self, action:#selector(tapClick(sender:)))

// 添加到 UIView 上
itemView.addGestureRecognizer(tap)
homeMusicScrollView.addSubview(itemView)

接收

同样的道理

@objc func tapClick(sender: UIGestureRecognizer){
    let itemView = sender.view!
    print(itemView.tag)
}