我如何利用django rest_framework才能生成这样类型的URL

Question

问题: 怎么才能实现 和drf最佳实践里面 类似的url
GET /cars/711/drivers/ Returns a list of drivers for car 711
GET /cars/711/drivers/4 Returns driver #4 for car 711

代码:

model

class Car(models.Model):
    name = models.CharField(u'车名', max_length=10)


class Driver(models.Model):
    name = models.CharField(u'人名',max_length=10)
    car = models.ForeignKey(Car, related_name='drivers', verbose_name='司机')

serializers

class CarSerializer(serializers.ModelSerializer):
    class Meta:
        model = Car
        fields = ('name',)


class DriverSerializer(serializers.ModelSerializer):
    car = CarSerializer(many=False)
    class Meta:
        model = Driver
        fields = ('name', 'car')

views:

class CarViewSet(viewsets.ModelViewSet):
    queryset = Car.objects.all()
    serializer_class = CarSerializer


class DriverSerializer(viewsets.ModelViewSet):
    queryset = Driver.objects.all()
    serializer_class = DriverSerializer
    

urls：

root_router = DefaultRouter()

root_router.register(r'cars', CarViewSet, base_name='cars')

Answer 1

可以这样解决，直接写一个view

# urls.py
url(r'cars/(?P<pk>[0-9]+)/dirvers/(?P<dirver_pk>[0-9]+)?',
            car_dirvers))
            
# views.py            
def car_dirvers(request, pk, dirver_pk=None):
    car = Car.objects.get(pk=pk)
    if dirver_pk is None:
        serializer = DriverSerializer(car.drivers.all(), many=True)
    else:
        serializer = DriverSerializer(car.drivers.get(pk=dirver_pk), many=False)
    return JsonResponse(serializer.data, safe=False)
    

代码地址
https://github.com/uxlsl/myco...