Python3 Scrapy框架中进入callback函数，但第一级取的值存入数据库中都重复

Question

-- coding: utf-8 --

import scrapy,re
from scrapy.selector import Selector
from scrapy.http import Request
from novelspider.items import NovelspiderItem
import re

class novelSpider(scrapy.Spider):

name = 'novelSpider'
allowed_domains = ["www.tibetif.com"]
url = "http://www.tibetif.com/index.php?m=content&c=index&a=lists&catid=955"
start_urls = [url]

def parse(self, response):
    item = NovelspiderItem()
    list = response.xpath(".//table[@class='proinfo']/tbody/tr")
    for i in range(2,len(list)):
        item['projectNo'] = list[i].xpath(".//td/text()").extract()[0].strip()
        item['url'] = list[i].xpath(".//td[2]/a/@href").extract()[0]
        item['title'] = list[i].xpath(".//td[2]/a/text()").extract()[0]
        item['money'] = list[i].xpath(".//td[4]/text()").extract()[0]
        item['date'] = list[i].xpath(".//td[5]/text()").extract()[0]
        yield scrapy.Request(item['url'],meta={'item':item},callback=self.detail)

def detail(self,response):
    item = response.meta['item']
    selector = Selector(response)
    text = selector.xpath(".//div[@class='wrapper']/table[3]").xpath('string(.)').extract()[0].replace("\n"," ").replace("\t"," ").replace("\r"," ").strip('\n').strip('\t').strip('\r').lstrip().rstrip()
    print(item['title'])
    companyObj = re.search(r'标的企业名称\s*(\S+)',text)
    if companyObj:
        item['company'] = str(companyObj.group(1))
    priceObj = re.search(r'注册资本\(元\)\s*(\S+)',text)
    if priceObj:
        item['price'] = str(priceObj.group(1))
    return item
    
    

问题：Python3 Scrapy框架中不进入yield scrapy.Request(item['url'],meta={'item':item},callback=self.detail)中的callback=self.detail函数，导致数据库中在parse函数中取得的值都是最后一个页面的值

Answer 1

scrapy框架出python3版本了吗

Answer 2

Python3已经支持scrapy啊

Answer 3

亲测可以进入detail

感觉你最好yeild item试试？

Answer 4

你把detail的最后一行 return item 改成 yield item试试