react-router4 跳转其他组件失败

Question

怎么实现点击链接，second组件是新页面展示，而不是在当前页面展示呢!地址栏的路由对了，但是不能跳转

index.js

import React from 'react';
import ReactDOM from 'react-dom';
import './index.css';
import App from './App';
import { Route,BrowserRouter}from 'react-router-dom';
import registerServiceWorker from './registerServiceWorker';
import home from './components/home';
import second from './components/second'
ReactDOM.render((
  <BrowserRouter>
    <div>
      <App>
          <Route path = '/' component={home}></Route>
      </App>
        <Route path = '/second' component={second}></Route>
    </div>


  </BrowserRouter>
),document.getElementById('root'));

registerServiceWorker();

App.js

import React, { Component } from 'react';
// import logo from './logo.svg';
import './App.css';
// import {Router, Route, Link,BrowserRouter,HashRouter,hashHistory,Indexlink,Match}from 'react-router-dom';
import {Link} from 'react-router-dom'
class App extends Component {
  render() {
    return (
      <div className="App">
        <h1>hello,world</h1>

        {this.props.children}
      </div>

    );
  }

}

export default App;

home.js

import React, { Component } from 'react';
// import logo from './logo.svg';

// import {Router, Route, Link,BrowserRouter,HashRouter,hashHistory,Indexlink,Match}from 'react-router-dom';
import {Link} from 'react-router-dom'
class myHome extends Component {
  render() {
    return (
      <div className="myHome">
        <h1>home页面</h1>
      <Link to="/second">点击点击</Link>

      </div>
    );
  }
}
export default myHome;

Answer 1

在<Route path = '/second' component={second}></Route>中添加exact属性就可以了。
如下：

<Route exact path = '/second' component={second}></Route>

Answer 2

请把错误信息和second页面的代码贴出来