Android socket代码无法运行

Question

public class MainActivity extends Activity {
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        Thread thread=new Thread(new Runnable()  
        {  
            @Override  
            public void run()  
            {
                System.out.println("Hello World!");
                try {
                    ServerSocket ss = new ServerSocket(8888);
                    System.out.println("启动服务器....");
                    Socket s = ss.accept();
                    System.out.println("客户端:"+s.getInetAddress().getLocalHost()+"已连接到服务器");

                    BufferedReader br = new BufferedReader(new InputStreamReader(s.getInputStream()));
                    //读取客户端发送来的消息
                    String mess = br.readLine();
                    System.out.println("客户端："+mess);
                    BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(s.getOutputStream()));
                    bw.write(mess+"\n");
                    bw.flush();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        });  
        thread.start(); 
    }

以上是一段网上找来的代码，在IntelliJ IDEA下可以正常运行，可以观察到8888端口处于listen状态。
最近在学习Android编程，用Android Studio把以上代码核心部分复制到MainActivity.java中，然后可以运行，以下为控制台输出内容:

Client not ready yet..Waiting for process to come online
Connected to process 4234 on device Nexus_5X_API_27_x86 [emulator-5554]
Capturing and displaying logcat messages from application. This behavior can be disabled in the "Logcat output" section of the "Debugger" settings page.
I/zygote: Not late-enabling -Xcheck:jni (already on)
W/zygote: Unexpected CPU variant for X86 using defaults: x86
I/InstantRun: starting instant run server: is main process
I/System.out: Hello World!
I/System.out: 启动服务器....
D/OpenGLRenderer: HWUI GL Pipeline
I/zygote: android::hardware::configstore::V1_0::ISurfaceFlingerConfigs::hasWideColorDisplay retrieved: 0
I/OpenGLRenderer: Initialized EGL, version 1.4
D/OpenGLRenderer: Swap behavior 1
W/OpenGLRenderer: Failed to choose config with EGL_SWAP_BEHAVIOR_PRESERVED, retrying without...
D/OpenGLRenderer: Swap behavior 0
D/EGL_emulation: eglCreateContext: 0x9d4050c0: maj 3 min 1 rcv 4
D/EGL_emulation: eglMakeCurrent: 0x9d4050c0: ver 3 1 (tinfo 0x9d403300)
E/eglCodecCommon: glUtilsParamSize: unknow param 0x000082da
E/eglCodecCommon: glUtilsParamSize: unknow param 0x000082da
E/eglCodecCommon: glUtilsParamSize: unknow param 0x00008cdf
E/eglCodecCommon: glUtilsParamSize: unknow param 0x00008cdf
E/eglCodecCommon: glUtilsParamSize: unknow param 0x00008824
E/eglCodecCommon: glUtilsParamSize: unknow param 0x00008824
D/EGL_emulation: eglMakeCurrent: 0x9d4050c0: ver 3 1 (tinfo 0x9d403300)

此时发现8888端口并没有处于Listen状态，而且也无法与client端进行通信。
请问各位，问题可能会出在哪里？多谢了。

Answer 1

简而言之, 举个例子.
假设你在你朋友的手机上运行你的这个程序,监听 8888 端口, 运行一切正常.
现在问题来了: 请问,你电脑上的 8888 端口会处于 Listen 状态吗?

Answer 2

没写IP地址