无法获取到https.get的返回值

Question

const https = require('https');
const WXBizDataCrypt = require('./WXBizDataCrypt.js');

const getSessionKey = (jsCode,iv,encryptedData) => {
    const Appid = 'your appId';
    const AppSecret = 'your appSecret';

    let url = 'https://api.weixin.qq.com/sns/jscode2session?appid='+Appid+'&secret='+AppSecret+'&js_code='+jsCode+'&grant_type=authorization_code';

    https.get( url , (response) => {
        let body = [];

        // console.log(response.statusCode);
        // console.log(response.headers);

        response.on('data', (chunk) => {
            body.push(chunk);
        });

        response.on('end', () => {
            // body = Buffer.concat(body);
            let data = Buffer.concat(body).toString();
            let getData = JSON.parse(data);
            // console.log(data);
            // console.log({
            //     session_key: getData.session_key
            // });
            let sessionKey = getData.session_key;
            // console.log(sessionKey);

            let pc = new WXBizDataCrypt(Appid, sessionKey)

            let getPhone = pc.decryptData(encryptedData , iv)

            let phone = getPhone.phoneNumber;

            console.log('解密后 phone: ', phone)

            return phone;

        });

    });
    
}

let jsCode = 'your jsCode';
let iv = 'your iv';
let encryptedData = 'your encryptedData';

getSessionKey(jsCode,iv,encryptedData);

return phone这个值怎么拿到

Answer 1

肯定是不能用return的，异步的特性。
es6不熟悉
用常规的思路大概写一下

getSessionKey(...,callbackFn){
    ...
    callbackFn(phone)
}

function callbackFn(phone){
    //在这里处理你要对phone的操作
}
getSessionKey(...,callbackFn);