将一段序列 排序，去重，以列表和字典形式打印

Question

问题：将l = '0:13 1:9 2:14 4:12 3:19 3:25 3:19 3:14'进行去重和排序

想要的列表为：['0:13', '1:9', '2:14', '3:14', '3:19', '3:25', '4:12']
想要的字典为：{'0': '0:13', '1': '1:9', '2': '2:14', '3': '3:14,3:19,3:25', '4': '4:12'}

欢迎大家来指点
万分感谢！！！

Answer 1

split 分割
set 去重
list 列表
sort 排序
enumerate 索引 值
dict 字典

Answer 2

    from collections import defaultdict
    
    
    l = '0:13 1:9 2:14 4:12 3:19 3:25 3:19 3:14'
    a_list = []
    l_dict = defaultdict(lambda: set())
    a_dict = {}
    for i in l.split(" "):
        l_dict[int(i.split(":")[0])].add(int(i.split(":")[1]))
    for n in sorted(l_dict.items(), key=lambda x: x[0]):
        tmp_l = []
        for m in sorted(n[1]):
            tmp_l.append("{}:{}".format(n[0], m))
        a_list += tmp_l
        a_dict[str(n[0])] = ",".join(tmp_l)

Answer 3

列表:

list1 = l.split(' ')
list1 = list(set(list1))  #去重
list1.sort(key=lambda x:x[0]) #排序

字典:

from collections import defaultdict
d = defaultdict(list)
for i in list1:
    d[i[0]].append(i)
for index, items in d.items():
    d[index] = ",".join(items)

Answer 4

l.split()
{str(k):v for k, v in enumerate(l.split())}

Answer 5

试试

print sorted(list(set(l.split(' '))),key=lambda x:x.split(':')[0])
print dict((i.split(':')[0],i.split(':')[1]) for i in list1)