关于python zeromq的Publish-Subscribe模式的问题

Question

我用如下的pub端代码往所有地址广播消息，

#-*-coding:utf-8-*-

import zmq.green as zmq

context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:5559")

while True:
    msg = raw_input('input your data:')
    socket.send(msg)

请问能否在这里限制，只有包含过滤条件的“sub”端才能来连接并接收消息呢？