ConcurrentHashMap中的get()方法为什么可以不加锁？

Question

 public V get(Object key) {
        Segment<K,V> s; // manually integrate access methods to reduce overhead
        HashEntry<K,V>[] tab;
        int h = hash(key);
        long u = (((h >>> segmentShift) & segmentMask) << SSHIFT) + SBASE;
        if ((s = (Segment<K,V>)UNSAFE.getObjectVolatile(segments, u)) != null &&
            (tab = s.table) != null) {
            for (HashEntry<K,V> e = (HashEntry<K,V>) UNSAFE.getObjectVolatile
                     (tab, ((long)(((tab.length - 1) & h)) << TSHIFT) + TBASE);
                 e != null; e = e.next) {
                K k;
                if ((k = e.key) == key || (e.hash == h && key.equals(k)))
                    return e.value;
            }
        }
        return null;
    }

为什么Vector的get就需要使用synchronized来加锁而ConcurrentHashMap则不需要？而且CopyOnWriteArrayList也是使用了写时复制还能实现读写并行，而显然ConcrrentHashMap并没有实现写时复制，它是怎么保证读写并行时不会读取到不一致中间状态的呢？

Answer 1

这篇文章解释的挺好的