怎么用函数将一个关联数据里第一个下标的值和第二个下标的值对应起来？

Question

$rs = [

"h" => ["id", "name", "region"],
"d" => [
    [100, "wang", "shanghai"],
    [101, "huang", "beijing"],
    [102, "zhang", "beijing"],
    [103, "li", "shanghai"],
]

];

$ret = rs2Array($rs);
print json_encode($ret);
/* 期望结果为:
[

{id: 100, name: "wang", region: "shanghai"},
{id: 101, name: "huang", region: "beijing"},
{id: 102, name: "zhang", region: "beijing"},
{id: 103, name: "li", region: "shanghai"}

]
*/

Answer 1

$rs = [
    "h" => ["id", "name", "region"],
    "d" => [
        [100, "wang", "shanghai"],
        [101, "huang", "beijing"],
        [102, "zhang", "beijing"],
        [103, "li", "shanghai"],
    ]
];

foreach ($rs['d'] as $v) {
    $arr[] = array_combine($rs['h'], $v);
}

var_dump(json_encode($arr));

Answer 2

$rs = [
    "h" => ["id", "name", "region"],
    "d" => [
        [100, "wang", "shanghai"],
        [101, "huang", "beijing"],
        [102, "zhang", "beijing"],
        [103, "li", "shanghai"],
    ]
];
$ret = rs2Array($rs);
print json_encode($ret);

rs2Array函数如下：

function rs2Array($arr = []) {
    $keyArr = $arr['h'];
    $valueArr = $arr['d'];
    return array_map(function($a) use($keyArr) {
        return array_combine($keyArr, $a);
    }, $valueArr);
}