数组重新组合

Question

1,如何将数组arr1转化成arr2?

arr1 = [

['tracking1','abc@qq.com','80'],
['tracking1','abc@qq.com','50'],
['tracking2','efg@qq.com','60'],
['tracking2','efg@qq.com','30'],

];

arr2 = [

['tracking1','abc@qq.com',['80','50']],
['tracking2','efg@qq.com',['60','30']],

];

Answer 1

思路很简单，就是把数组的第一和第一列的值作为一个唯一key写入，感觉楼上代码有点多，简洁代码如下

$arr1 = [
    ['tracking1','abc@qq.com','80'],
    ['tracking1','abc@qq.com','50'],
    ['tracking2','efg@qq.com','60'],
    ['tracking2','efg@qq.com','30'],
];

$arr2 = [];
foreach ($arr1 as $data) {
    list($account,$mail,$val) = $data;
    isset($arr2[$account.$mail]) || $arr2[$account.$mail]=[$account,$mail,[]];
    array_push($arr2[$account.$mail][2],$val);
}
$arr2 = array_values($arr2);
var_dump($arr2);

Answer 2

我给个思路，先遍历判断arr1[0]是否一样，一样就往一个新数组中插入，在这基础判断[1]是否相同，相同就插入值，不同则合并成一个数组，以此类推

Answer 3

$arr = [['tracking1','abc@qq.com','80'],
['tracking1','abc@qq.com','50'],
['tracking2','efg@qq.com','60'],
['tracking2','efg@qq.com','30']];

$finalArr = [[[]]];
$mailArr =[];
foreach ($arr as $k=>$v){
    $mailKey = array_search($v[1],$mailArr);
    if($mailKey!==false){
        array_push($finalArr[$mailKey][2],$v[2]);
    }else{
        $finalArr[$k] = $v;
        $finalArr[$k][2] = [$v[2]];
        $mailArr[$k]=$v[1];
    }
}
$finalArr = array_values($finalArr);
var_dump($finalArr);

14行功能代码，不要太简单。

Answer 4

说下我的思路，题主这个数组，拆分开其实就是两个部分，每个数组里的v0、v1值，和v2值。

$new = array(); 
$flag = 1;
foreach ($arr as $key => $value) {
  $newss[$value[0].'-'.$value[1]][] = $value[2];  //取出重复小标0 1的值 
  $news = array($value[0], $value[1]);
  foreach ($new as $k => $v) {
    if(!array_diff($v,$news )) { //如果
      $flag = 2;
      break;
    }
  }
  if($flag == 1) {
    $new[] = array($value[0], $value[1]);
  }
  $flag = 1;
}
foreach ($new as $key => $value) {
  $new[$key][2] = $newss[$value[0].'-'.$value[1]];
}
var_dump($new);exit;

Answer 5

    $arr1 = [    
        ['tracking1','abc@qq.com','80'],
        ['tracking1','abc@qq.com','50'],
        ['tracking2','efg@qq.com','60'],
        ['tracking2','efg@qq.com','30'],
    ];
    
    $arr2 = [
        ['tracking1','abc@qq.com',['80','50']],
        ['tracking2','efg@qq.com',['60','30']],
    ];

    define("CUSTOM_SEPA", "_");

    function t($a0){
        $r = [];
        $res = [];
        foreach($a0 as $v){
            $r[$v[0].CUSTOM_SEPA.$v[1]][] = $v[2];
        }
        foreach($r as $k=>$v){
            $s = explode(CUSTOM_SEPA, $k);
            $s[] = $v;
            $res[] = $s;
        }
        return $res;
    }

    $res = t($arr1);
    print_r($res == $arr2);