medoo怎么在column参数中使用sql函数？

Question

SELECT COUNT(distinct(uid)) FROM nazou.items_want 

有时候需要像上面那条那样，查一下某个表里有哪些uid，使用medoo的count方法，怎么做到上面那条语句那样的功能？

Answer 1

已解决我目前的版本是1.4.5

修改
protected function columnPush(&$columns)

{
    if ($columns === '*')
    {
        return $columns;
    }

    $stack = [];

    if (is_string($columns))
    {
        $columns = [$columns];
    }

    foreach ($columns as $key => $value)
    {

        preg_match('/^#([a-zA-Z0-9_\-]*)\(([a-zA-Z0-9_\-\.]*)\)\s*(\(([a-zA-Z0-9_\-]*)\))?/i', $value, $match);

        if(isset($match[1], $match[2])){

            $column_fn = $match[1] . '('. $this->columnQuote( $match[2] ) . ')';

            if( count($match) === 5 ){
                array_push($stack, $column_fn . ' AS ' . $this->columnQuote( $match[4] ));
            }else{
                array_push($stack, $column_fn);
            }

        }else{

            preg_match('/([a-zA-Z0-9_\-\.]*)\s*\(([a-zA-Z0-9_\-]*)\)/i', $value, $match);

            if (isset($match[1], $match[2]))
            {
                array_push($stack, $this->columnQuote( $match[1] ) . ' AS ' . $this->columnQuote( $match[2] ));
            }
            else
            {
                array_push($stack, $this->columnQuote( $value ));
            }
        }
    }

    return implode($stack, ',');
}
并且修改select方法最后部分
 while ($data = $query->fetch(PDO::FETCH_ASSOC))
    {
       // $current_stack = [];

        //$this->dataMap($data, $columns, $column_map, $current_stack);

        $stack[$index] = $data;
       
        $index++;
    }

    return $stack;

Answer 2

$db->select(table, [
'cnt' => Medoo::raw('count(distinct uid))')
]);