关于Python matplotlib pyplot的问题

Question

我想得到两张折线图，关于微软和英特尔的股票数据的，代码如下

import time
from matplotlib.finance import quotes_historical_yahoo_ochl
from datetime import date
from datetime import datetime
import pandas as pd
import matplotlib.pyplot as plt
import pylab as pl
import numpy as np
start = datetime(2014,1,1)
end = datetime(2014,12,31)
print start
quotesMSFT = quotes_historical_yahoo_ochl('MSFT',start,end)
quotesINTC = quotes_historical_yahoo_ochl('INTC',start,end)
fieIds = ['date', 'open', 'close', 'high', 'low', 'volume']
list1=[]
for i in range(0,len(quotesMSFT)):
    x = date.fromordinal(int(quotesMSFT[i][0]))
    y= datetime.strftime(x,"%Y-%m-%d")
    list1.append(y)

list2=[]
for i in range(0,len(quotesINTC)):
    x= date.fromordinal(int(quotesINTC[i][0]))
    y= datetime.strftime(x, "%Y-%m-%d")
    list2.append(y)
quotesmsftdf=pd.DataFrame(quotesMSFT,index=list1,columns=fieIds)
quotesmsftdf=quotesmsftdf.drop(['date'],axis=1)
quotesintcdf= pd.DataFrame(quotesINTC,index=list2,columns=fieIds)
quotesintcdf= quotesintcdf.drop(['date'],axis=1)
listtemp1= []
for i in range(0,len(quotesmsftdf)):
    temp=time.strptime(quotesmsftdf.index[i], "%Y-%m-%d")
    listtemp1.append(temp.tm_mon)
listtemp2 = []
for i in range(0,len(quotesintcdf)):
    temp=time.strptime(quotesintcdf.index[i], "%Y-%m-%d")
    listtemp2.append(temp.tm_mon)
tempmsftdf=quotesmsftdf.copy()
tempmsftdf['month'] = listtemp1
closemaxMSFT = tempmsftdf.groupby('month').max().close
listMSFT= []
for i in range(1,13):
    listMSFT.append(closemaxMSFT[i])
listMSFTIndex= closemaxMSFT.index
tempintcdf= quotesintcdf.copy()
tempintcdf['month']=listtemp2
closemaxINTC = tempintcdf.groupby('month').max().close
listINTC = []
for i in range(1,13):
    listINTC.append(closemaxINTC[i])
listINTCIndex = closemaxINTC.index
pl.subplot(211)
plt.plot(listMSFTIndex,listMSFT,color='r',marker='o')
pl.subplot(212)
plt.plot(listINTCIndex,listINTC,color='green',marker='o')

程序运行时没有报错，但是图表却没有显示出来，用的是pycharm

Answer 1

在最后加上
plt.show()