java如何用json解析数组?
{"asks":[[3949,136.857],[3948.88,0.083],[3948.42,0.01],[3948,16.251],[3947.27,0.126],[3947,0.418],[3946.03,1.219],[3945.59,0.01],[3945,0.01],[3944,0.01],[3943.04,3.393],[3942.67,0.01],[3940,41.151],[3939.99,5],[3939.7,1],[3939,1],[3938.59,0.01],[3938,1.81],[3936.5,0.1],[3934.64,0.1],[3934.56,0.1],[3934,0.05],[3933.27,0.5],[3933,0.2],[3932.83,28],[3932,0.01],[3931,0.697],[3930,43.02],[3929.99,5],[3929.2,0.841],[3929,24.41],[3928.02,2],[3927,15.645],[3926.37,6],[3926.02,0.689],[3926,0.51],[3925.5,25.753],[3925,0.63],[3924.88,0.24],[3924.83,0.01],[3924.8,9.478],[3923,0.2],[3922.99,0.3],[3922,0.5],[3921,0.01],[3920.99,0.3],[3920.05,0.2],[3920,0.01],[3919.9,3.701],[3919.89,0.71],[3919,0.01],[3918.99,0.831],[3918.27,0.07],[3918,0.01],[3917,0.34],[3916.99,0.3],[3916,0.01],[3915,30.01],[3914.98,1.894],[3914.96,0.052]],"bids":[[3914.07,0.24],[3914.05,1.62],[3914.02,1.269],[3914,3.747],[3913,0.01],[3912.54,0.018],[3912,0.01],[3911.49,2.627],[3911,0.01],[3910.1,0.04],[3910,0.01],[3909,0.67],[3908,0.01],[3907,1.01],[3906.1,5],[3906.01,0.3],[3906,0.01],[3905,8.21],[3904.01,0.3],[3904,0.01],[3903,0.01],[3902.01,0.3],[3902,0.01],[3901,1.29],[3900.5,0.7],[3900.15,0.78],[3900.14,0.01],[3900.01,0.3],[3900,5.93],[3899.86,0.03],[3899,0.01],[3898.01,0.3],[3898,0.01],[3897.63,6],[3897,0.01],[3896.5,3.251],[3896.01,0.3],[3896,0.01],[3895,0.01],[3894.14,0.01],[3894.01,0.3],[3894,0.01],[3893,0.01],[3892.01,0.3],[3892,0.01],[3891.03,0.01],[3891,0.01],[3890.37,1.058],[3890.01,0.3],[3890,4.182],[3889,1.45],[3888.01,0.3],[3888,1.81],[3887.91,0.01],[3887,0.01],[3886.01,0.3],[3886,0.01],[3885,5.61],[3884.4,0.01],[3884.01,0.3]]}
这样一串如何解析?里面[3886.01,0.3] 这样一个左边代表价格(3886.01),右边代表数量(0.3) 如何解析?
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先格式化。http://jsonlint.com/
然后按照数组一个一个解析。。
java的JSON库有很多
json.org:
http://www.json.org/java/index.html
阿里巴巴的fastjson:
https://github.com/alibaba/fastjson
minimal-json:
https://github.com/ralfstx/minimal-json
使用第三方jar包进行解析。可以直接将json串解析成对象。能应付一般工作了。
google也有一个json包,google-gson http://https://code.google.com/p/google-gson/