PHP-一个php 数组取值问题

Question

$arr1 = array(0 => string '126', 1 => string '137');
$arr2 = array(0 => string '126', 1 => string '136,137');
怎么样才能获取到
array(1 => '136')

或者
$arr1 = array(0 => string '126,127', 1 => string '136,137');
$arr2 = array(0 => string '126', 1 => string '136');

怎么样才能获取到
array(0 => '127', 1 => '136')

key和val必须对应。

Answer 1

下面的代码能实现你的要求：

$arr1 = array(0 => '126', 1 => '137');
$arr2 = array(0 => '126', 1 => '136,137');
$result = array();
foreach($arr1 as $key =>$value){
if($arr2[$key] != $value){
$result[$key] = implode(',', (array_diff(explode(',',$arr2[$key]),explode(',',$value) ) ) );
}
}
var_dump($result);

Answer 2

有点不明白你的意思，
如果是取差集，
用上面array_diff和array_intersect遍历匹配就可以，
但是你给的第二个例子是和第一个是没有个规律可言的
如果是这样的话，
那个人认为只能去设定固定值去遍历匹配到数组了

Answer 3

或者后面的结果

$arr1 = array('126,127','136,137');
$arr2 = array('126','136');
$arr = array();
foreach ($arr1 as $k=>$v){
$arr[$k] = explode(',', $v);
}
foreach ( $arr as $k=>$v){
if ($k%2==0){
$a[] = implode('',array_diff($v, $arr2));
}else {
$a[] = implode('',array_intersect($v, $arr2));
}
}
print_r($a);