Shell-关于shell获得执行结果的问题？

Question

我想获得curl -i ‘www.xxx.com’执行后的结果，并赋予变量，正常在命令行输出的结果是

HTTP/1.1 302 Moved Temporarily
Server: nginx/0.8.54
Date: Thu, 07 Jun 2012 06:11:13 GMT
Content-Type: text/html; charset=utf-8
Transfer-Encoding: chunked
Connection: keep-alive
X-Powered-By: PHP/5.3.6
Set-Cookie: PHPSESSID=d33ac5thh2b4c3r5fujp8gsia6; path=/
Expires: Thu, 19 Nov 1981 08:52:00 GMT
Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0
Pragma: no-cache

Answer 1

 #!/bin/sh

tmpfile="/root/tmp1.txt"
curl -s -I "http://www.baidu.com" > ${tmpfile}
dos2unix -q ${tmpfile}

while read line
do
curl_result="${curl_result}${line}"
done < ${tmpfile}

echo ${curl_result}

Answer 2

查看man curl

PROGRESS METER
curl normally displays a progress meter during operations, indicating the amount of transferred data, transfer speeds and estimated time left, etc.curl displays this data to the terminal by default, so if you invoke curl to do an operation and it is about to write data to the terminal, it disables the progress meter as otherwise it would mess up the output mixing progress meter and response data.

很简单，你只需要使用-s选项(--silient)禁用PROGRESS METER就行了。
-s, --silent
Silent or quiet mode. Don't show progress meter or error messages. Makes Curl mute.

 response=`curl -I "http://www.example.com/" -s`

Answer 3

 json=$(curl -s http://www.test.com);
echo $json;