PHP-php如何以参数方式调用对象的方法,即$this->functionname()的functionname可以由变量传入

Question

<?php
class obj{
    public $functionname;
    
    function drawMain(){
            echo ' in function drawMain()<br/>';
    }
         function drawPart(){
            echo ' in function drawPart()<br/>';
    }
    
    function __construct(){
            **$this->functionname='$this->drawMain'; //这样写对吗?**
    }
    
    function draw(){
            **$this->functionname(); //这句不知道该怎么写了**
    }
}
    $obj= new obj();
    
    **$obj->draw(); //希望能实现  $obj->drawMain();**
?>

Answer 1

你可以这样做

<?php
class obj{
public $functionname;

function drawMain(){
echo ' in function drawMain()<br/>';
}
function drawPart(){
echo ' in function drawPart()<br/>';
}

function __construct(){
$this->functionname='drawMain';
}

function draw(){
call_user_func_array( array( $this, $this->functionname ) , array() ) ;
}
}
$obj= new obj();

$obj->draw();
?>