Question

2820. Election Results

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Description

Table: Votes

+-------------+---------+ 
| Column Name | Type  | 
+-------------+---------+ 
| voter     | varchar | 
| candidate   | varchar |
+-------------+---------+
(voter, candidate) is the primary key (combination of unique values) for this table.
Each row of this table contains name of the voter and their candidate. 

The election is conducted in a city where everyone can vote for one or more candidates or choose not to vote. Each person has 1 vote so if they vote for multiple candidates, their vote gets equally split across them. For example, if a person votes for 2 candidates, these candidates receive an equivalent of 0.5 votes each.

Write a solution to find candidate who got the most votes and won the election. Output the name of the candidate or If multiple candidates have an equal number of votes, display the names of all of them.

Return_ the result table ordered_ _by_ candidate _in ascending order._

The result format is in the following example.

 

Example 1:

Input: 
Votes table:
+----------+-----------+
| voter  | candidate |
+----------+-----------+
| Kathy  | null    |
| Charles  | Ryan    |
| Charles  | Christine |
| Charles  | Kathy   |
| Benjamin | Christine |
| Anthony  | Ryan    |
| Edward   | Ryan    |
| Terry  | null    |
| Evelyn   | Kathy   |
| Arthur   | Christine |
+----------+-----------+
Output: 
+-----------+
| candidate | 
+-----------+
| Christine |  
| Ryan    |  
+-----------+
Explanation: 
- Kathy and Terry opted not to participate in voting, resulting in their votes being recorded as 0. Charles distributed his vote among three candidates, equating to 0.33 for each candidate. On the other hand, Benjamin, Arthur, Anthony, Edward, and Evelyn each cast their votes for a single candidate.
- Collectively, Candidate Ryan and Christine amassed a total of 2.33 votes, while Kathy received a combined total of 1.33 votes.
Since Ryan and Christine received an equal number of votes, we will display their names in ascending order.

Solutions

Solution 1: Window Function + Group Statistics

We can use the window function count to calculate the number of votes each voter gives to the candidates, then use the group statistics function sum to calculate the total number of votes for each candidate. Next, we use the window function rank to calculate the ranking of each candidate, and finally filter out the candidate who ranks first.

Note that there may be multiple candidates ranking first in the result set, so we need to use order by to sort the candidates.

# Write your MySQL query statement below
WITH
  T AS (
    SELECT candidate, SUM(vote) AS tot
    FROM
      (
        SELECT
          candidate,
          1 / (COUNT(candidate) OVER (PARTITION BY voter)) AS vote
        FROM Votes
        WHERE candidate IS NOT NULL
      ) AS t
    GROUP BY 1
  ),
  P AS (
    SELECT
      candidate,
      RANK() OVER (ORDER BY tot DESC) AS rk
    FROM T
  )
SELECT candidate
FROM P
WHERE rk = 1
ORDER BY 1;