Question

973. K Closest Points to Origin

中文文档

Description

Given an array of points where points[i] = [xi, yi] represents a point on the X-Y plane and an integer k, return the k closest points to the origin (0, 0).

The distance between two points on the X-Y plane is the Euclidean distance (i.e., √(x1 - x2)2 + (y1 - y2)2).

You may return the answer in any order. The answer is guaranteed to be unique (except for the order that it is in).

 

Example 1:

Input: points = [[1,3],[-2,2]], k = 1
Output: [[-2,2]]
Explanation:
The distance between (1, 3) and the origin is sqrt(10).
The distance between (-2, 2) and the origin is sqrt(8).
Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin.
We only want the closest k = 1 points from the origin, so the answer is just [[-2,2]].

Example 2:

Input: points = [[3,3],[5,-1],[-2,4]], k = 2
Output: [[3,3],[-2,4]]
Explanation: The answer [[-2,4],[3,3]] would also be accepted.

 

Constraints:

• 1 <= k <= points.length <= 104
• -104 <= xi, yi <= 104

Solutions

Solution 1

class Solution:
  def kClosest(self, points: List[List[int]], k: int) -> List[List[int]]:
    points.sort(key=lambda p: p[0] * p[0] + p[1] * p[1])
    return points[:k]

class Solution {
  public int[][] kClosest(int[][] points, int k) {
    Arrays.sort(points, (a, b) -> {
      int d1 = a[0] * a[0] + a[1] * a[1];
      int d2 = b[0] * b[0] + b[1] * b[1];
      return d1 - d2;
    });
    return Arrays.copyOfRange(points, 0, k);
  }
}

class Solution {
public:
  vector<vector<int>> kClosest(vector<vector<int>>& points, int k) {
    sort(points.begin(), points.end(), [](const vector<int>& a, const vector<int>& b) {
      return a[0] * a[0] + a[1] * a[1] < b[0] * b[0] + b[1] * b[1];
    });
    return vector<vector<int>>(points.begin(), points.begin() + k);
  }
};

func kClosest(points [][]int, k int) [][]int {
  sort.Slice(points, func(i, j int) bool {
    a, b := points[i], points[j]
    return a[0]*a[0]+a[1]*a[1] < b[0]*b[0]+b[1]*b[1]
  })
  return points[:k]
}

function kClosest(points: number[][], k: number): number[][] {
  return points.sort((a, b) => a[0] ** 2 + a[1] ** 2 - (b[0] ** 2 + b[1] ** 2)).slice(0, k);
}

impl Solution {
  pub fn k_closest(mut points: Vec<Vec<i32>>, k: i32) -> Vec<Vec<i32>> {
    points.sort_unstable_by(|a, b| {
      (a[0].pow(2) + a[1].pow(2)).cmp(&(b[0].pow(2) + b[1].pow(2)))
    });
    points[0..k as usize].to_vec()
  }
}