Question

JavaScript => public function AddForceAtPosition(force: Vector3, position: Vector3, mode: ForceMode = ForceMode.Force): void;
C# => public void AddForceAtPosition(Vector3 force, Vector3 position, ForceMode mode = ForceMode.Force);

Parameters 参数

force	Force vector in world coordinates. 在世界坐标空间，力的向量。
position	Position in world coordinates. 在世界坐标空间的位置。

Description 描述

Applies force at position. As a result this will apply a torque and force on the object.

在position位置应用force力。作为结果这个将在这个物体上应用一个扭矩和力。

For realistic effects position should be approximately in the range of the surface of the rigidbody. This is most commonly used for explosions. When applying explosions it is best to apply forces over several frames instead of just one. Note that when position is far away from the center of the rigidbody the applied torque will be unrealistically large.

对于真实的效果，应大约在刚体表面的范围内的位置。这个最常用于爆炸，当应用于爆炸时，最好应用力到多帧而不是一帧中。注意当position远离刚体的中心时，所应用的力矩会不切实际地大。

Force can be applied only to an active rigidbody. If a GameObject is inactive, AddForceAtPosition has no effect.

力仅应用于激活的刚体。如果游戏对象未激活，AddForceAtPosition无效果。

Wakes up the Rigidbody by default. If the force size is zero then the Rigidbody will not be woken up.

默认刚体是唤醒的。如果力的大小为0，那么刚体不被唤醒。

See Also: AddForce, AddRelativeForce, AddTorque.

JavaScript:

	function ApplyForce (body : Rigidbody) {
		var direction : Vector3 = body.transform.position - transform.position;
		body.AddForceAtPosition(direction.normalized, transform.position);
	}

C#:

using UnityEngine;
using System.Collections;
 
public class ExampleClass : MonoBehaviour {
    void ApplyForce(Rigidbody body) {
        Vector3 direction = body.transform.position - transform.position;
        body.AddForceAtPosition(direction.normalized, transform.position);
    }
}

Rigidbody