Question

JavaScript => public static function DrawProcedural(topology: MeshTopology, vertexCount: int, instanceCount: int = 1): void;
C# => public static void DrawProcedural(MeshTopology topology, int vertexCount, int instanceCount = 1);

Parameters 参数

Description 描述

Draws a fully procedural geometry on the GPU.

在GPU中绘制程序上的几何结构。

DrawProcedural does a draw call on the GPU, without any vertex or index buffers. This is only useful on DirectX 11 or OpenGL Core level hardware where shaders can read arbitrary data from ComputeBuffer buffers.

DrawProcedural在GPU中进行绘制调用，没有任何顶点和索引缓存区。这仅用于DirectX 11或者OpenGL核心级硬件着色器可以从ComputeBuffer缓存区读取任何数据。

Note that this call executes immediately, similar to Graphics.DrawMeshNow. It uses currently set render target, transformation matrices and currently set shader pass.

注意该调用立即执行，近似于Graphics.DrawMeshNow。它使用当前设置渲染目标，转换矩阵和当前设置着色器路径。

There's also a similar functionality in CommandBuffers, see CommandBuffer.DrawProcedural.

还有一个在CommandBuffers中类似的功能,请参考CommandBuffer.DrawProcedural。

graphics