Question

2469. Convert the Temperature

中文文档

Description

You are given a non-negative floating point number rounded to two decimal places celsius, that denotes the temperature in Celsius.

You should convert Celsius into Kelvin and Fahrenheit and return it as an array ans = [kelvin, fahrenheit].

Return _the array ans. _Answers within 10-5 of the actual answer will be accepted.

Note that:

• Kelvin = Celsius + 273.15
• Fahrenheit = Celsius * 1.80 + 32.00

 

Example 1:

Input: celsius = 36.50
Output: [309.65000,97.70000]
Explanation: Temperature at 36.50 Celsius converted in Kelvin is 309.65 and converted in Fahrenheit is 97.70.

Example 2:

Input: celsius = 122.11
Output: [395.26000,251.79800]
Explanation: Temperature at 122.11 Celsius converted in Kelvin is 395.26 and converted in Fahrenheit is 251.798.

 

Constraints:

• 0 <= celsius <= 1000

Solutions

Solution 1: Simulation

We can directly simulate according to the problem description.

The time complexity is $O(1)$, and the space complexity is $O(1)$.

class Solution:
  def convertTemperature(self, celsius: float) -> List[float]:
    return [celsius + 273.15, celsius * 1.8 + 32]

class Solution {
  public double[] convertTemperature(double celsius) {
    return new double[] {celsius + 273.15, celsius * 1.8 + 32};
  }
}

class Solution {
public:
  vector<double> convertTemperature(double celsius) {
    return {celsius + 273.15, celsius * 1.8 + 32};
  }
};

func convertTemperature(celsius float64) []float64 {
  return []float64{celsius + 273.15, celsius*1.8 + 32}
}

function convertTemperature(celsius: number): number[] {
  return [celsius + 273.15, celsius * 1.8 + 32];
}

impl Solution {
  pub fn convert_temperature(celsius: f64) -> Vec<f64> {
    vec![celsius + 273.15, celsius * 1.8 + 32.0]
  }
}

/**
 * Note: The returned array must be malloced, assume caller calls free().
 */
double* convertTemperature(double celsius, int* returnSize) {
  double* ans = malloc(sizeof(double) * 2);
  ans[0] = celsius + 273.15;
  ans[1] = celsius * 1.8 + 32;
  *returnSize = 2;
  return ans;
}