Question

1083. Sales Analysis II

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Description

Table: Product

+--------------+---------+
| Column Name  | Type  |
+--------------+---------+
| product_id   | int   |
| product_name | varchar |
| unit_price   | int   |
+--------------+---------+
product_id is the primary key (column with unique values) of this table.
Each row of this table indicates the name and the price of each product.

Table: Sales

+-------------+---------+
| Column Name | Type  |
+-------------+---------+
| seller_id   | int   |
| product_id  | int   |
| buyer_id  | int   |
| sale_date   | date  |
| quantity  | int   |
| price     | int   |
+-------------+---------+
This table might have repeated rows.
product_id is a foreign key (reference column) to the Product table.
buyer_id is never NULL. 
sale_date is never NULL. 
Each row of this table contains some information about one sale.

 

Write a solution to report the buyers who have bought _S8_ but not _iPhone_. Note that _S8_ and _iPhone_ are products presented in the Product table.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Product table:
+------------+--------------+------------+
| product_id | product_name | unit_price |
+------------+--------------+------------+
| 1      | S8       | 1000     |
| 2      | G4       | 800    |
| 3      | iPhone     | 1400     |
+------------+--------------+------------+
Sales table:
+-----------+------------+----------+------------+----------+-------+
| seller_id | product_id | buyer_id | sale_date  | quantity | price |
+-----------+------------+----------+------------+----------+-------+
| 1     | 1      | 1    | 2019-01-21 | 2    | 2000  |
| 1     | 2      | 2    | 2019-02-17 | 1    | 800   |
| 2     | 1      | 3    | 2019-06-02 | 1    | 800   |
| 3     | 3      | 3    | 2019-05-13 | 2    | 2800  |
+-----------+------------+----------+------------+----------+-------+
Output: 
+-------------+
| buyer_id  |
+-------------+
| 1       |
+-------------+
Explanation: The buyer with id 1 bought an S8 but did not buy an iPhone. The buyer with id 3 bought both.

Solutions

Solution 1

# Write your MySQL query statement below
SELECT buyer_id
FROM
  Sales
  JOIN Product USING (product_id)
GROUP BY 1
HAVING SUM(product_name = 'S8') > 0 AND SUM(product_name = 'iPhone') = 0;