Question

690. Employee Importance

中文文档

Description

You have a data structure of employee information, including the employee's unique ID, importance value, and direct subordinates' IDs.

You are given an array of employees employees where:

• employees[i].id is the ID of the ith employee.
• employees[i].importance is the importance value of the ith employee.
• employees[i].subordinates is a list of the IDs of the direct subordinates of the ith employee.

Given an integer id that represents an employee's ID, return _the total importance value of this employee and all their direct and indirect subordinates_.

 

Example 1:

Input: employees = [[1,5,[2,3]],[2,3,[]],[3,3,[]]], id = 1
Output: 11
Explanation: Employee 1 has an importance value of 5 and has two direct subordinates: employee 2 and employee 3.
They both have an importance value of 3.
Thus, the total importance value of employee 1 is 5 + 3 + 3 = 11.

Example 2:

Input: employees = [[1,2,[5]],[5,-3,[]]], id = 5
Output: -3
Explanation: Employee 5 has an importance value of -3 and has no direct subordinates.
Thus, the total importance value of employee 5 is -3.

 

Constraints:

• 1 <= employees.length <= 2000
• 1 <= employees[i].id <= 2000
• All employees[i].id are unique.
• -100 <= employees[i].importance <= 100
• One employee has at most one direct leader and may have several subordinates.
• The IDs in employees[i].subordinates are valid IDs.

Solutions

Solution 1

"""
# Definition for Employee.
class Employee:
  def __init__(self, id: int, importance: int, subordinates: List[int]):
    self.id = id
    self.importance = importance
    self.subordinates = subordinates
"""


class Solution:
  def getImportance(self, employees: List['Employee'], id: int) -> int:
    m = {emp.id: emp for emp in employees}

    def dfs(id: int) -> int:
      emp = m[id]
      s = emp.importance
      for sub in emp.subordinates:
        s += dfs(sub)
      return s

    return dfs(id)

/*
// Definition for Employee.
class Employee {
  public int id;
  public int importance;
  public List<Integer> subordinates;
};
*/

class Solution {

  private final Map<Integer, Employee> map = new HashMap<>();

  public int getImportance(List<Employee> employees, int id) {
    for (Employee employee : employees) {
      map.put(employee.id, employee);
    }
    return dfs(id);
  }

  private int dfs(int id) {
    Employee employee = map.get(id);
    int sum = employee.importance;
    for (Integer subordinate : employee.subordinates) {
      sum += dfs(subordinate);
    }
    return sum;
  }
}

/**
 * Definition for Employee.
 * function Employee(id, importance, subordinates) {
 *   this.id = id;
 *   this.importance = importance;
 *   this.subordinates = subordinates;
 * }
 */

/**
 * @param {Employee[]} employees
 * @param {number} id
 * @return {number}
 */
var GetImportance = function (employees, id) {
  const map = new Map();
  for (const employee of employees) {
    map.set(employee.id, employee);
  }
  const dfs = id => {
    const employee = map.get(id);
    let sum = employee.importance;
    for (const subId of employee.subordinates) {
      sum += dfs(subId);
    }
    return sum;
  };
  return dfs(id);
};