Question

345. Reverse Vowels of a String

中文文档

Description

Given a string s, reverse only all the vowels in the string and return it.

The vowels are 'a', 'e', 'i', 'o', and 'u', and they can appear in both lower and upper cases, more than once.

 

Example 1:

Input: s = "hello"
Output: "holle"

Example 2:

Input: s = "leetcode"
Output: "leotcede"

 

Constraints:

• 1 <= s.length <= 3 * 105
• s consist of printable ASCII characters.

Solutions

Solution 1

class Solution:
  def reverseVowels(self, s: str) -> str:
    vowels = "aeiouAEIOU"
    i, j = 0, len(s) - 1
    cs = list(s)
    while i < j:
      while i < j and cs[i] not in vowels:
        i += 1
      while i < j and cs[j] not in vowels:
        j -= 1
      if i < j:
        cs[i], cs[j] = cs[j], cs[i]
        i, j = i + 1, j - 1
    return "".join(cs)

class Solution {
  public String reverseVowels(String s) {
    boolean[] vowels = new boolean[128];
    for (char c : "aeiouAEIOU".toCharArray()) {
      vowels[c] = true;
    }
    char[] cs = s.toCharArray();
    int i = 0, j = cs.length - 1;
    while (i < j) {
      while (i < j && !vowels[cs[i]]) {
        ++i;
      }
      while (i < j && !vowels[cs[j]]) {
        --j;
      }
      if (i < j) {
        char t = cs[i];
        cs[i] = cs[j];
        cs[j] = t;
        ++i;
        --j;
      }
    }
    return String.valueOf(cs);
  }
}

class Solution {
public:
  string reverseVowels(string s) {
    bool vowels[128];
    memset(vowels, false, sizeof(vowels));
    for (char c : "aeiouAEIOU") {
      vowels[c] = true;
    }
    int i = 0, j = s.size() - 1;
    while (i < j) {
      while (i < j && !vowels[s[i]]) {
        ++i;
      }
      while (i < j && !vowels[s[j]]) {
        --j;
      }
      if (i < j) {
        swap(s[i++], s[j--]);
      }
    }
    return s;
  }
};

func reverseVowels(s string) string {
  vowels := [128]bool{}
  for _, c := range "aeiouAEIOU" {
    vowels[c] = true
  }
  cs := []byte(s)
  i, j := 0, len(cs)-1
  for i < j {
    for i < j && !vowels[cs[i]] {
      i++
    }
    for i < j && !vowels[cs[j]] {
      j--
    }
    if i < j {
      cs[i], cs[j] = cs[j], cs[i]
      i, j = i+1, j-1
    }
  }
  return string(cs)
}

function reverseVowels(s: string): string {
  const vowels = new Set(['a', 'e', 'i', 'o', 'u']);
  const cs = s.split('');
  for (let i = 0, j = cs.length - 1; i < j; ++i, --j) {
    while (i < j && !vowels.has(cs[i].toLowerCase())) {
      ++i;
    }
    while (i < j && !vowels.has(cs[j].toLowerCase())) {
      --j;
    }
    [cs[i], cs[j]] = [cs[j], cs[i]];
  }
  return cs.join('');
}

impl Solution {
  pub fn reverse_vowels(s: String) -> String {
    let vowel = String::from("aeiouAEIOU");
    let mut data: Vec<char> = s.chars().collect();
    let (mut i, mut j) = (0, s.len() - 1);
    while i < j {
      while i < j && !vowel.contains(data[i]) {
        i += 1;
      }
      while i < j && !vowel.contains(data[j]) {
        j -= 1;
      }
      if i < j {
        data.swap(i, j);
        i += 1;
        j -= 1;
      }
    }
    data.iter().collect()
  }
}