返回介绍

solution / 1000-1099 / 1045.Customers Who Bought All Products / README_EN

发布于 2024-06-17 01:03:31 字数 2673 浏览 0 评论 0 收藏 0

1045. Customers Who Bought All Products

中文文档

Description

Table: Customer

+-------------+---------+
| Column Name | Type  |
+-------------+---------+
| customer_id | int   |
| product_key | int   |
+-------------+---------+
This table may contain duplicates rows. 
customer_id is not NULL.
product_key is a foreign key (reference column) to Product table.

 

Table: Product

+-------------+---------+
| Column Name | Type  |
+-------------+---------+
| product_key | int   |
+-------------+---------+
product_key is the primary key (column with unique values) for this table.

 

Write a solution to report the customer ids from the Customer table that bought all the products in the Product table.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Customer table:
+-------------+-------------+
| customer_id | product_key |
+-------------+-------------+
| 1       | 5       |
| 2       | 6       |
| 3       | 5       |
| 3       | 6       |
| 1       | 6       |
+-------------+-------------+
Product table:
+-------------+
| product_key |
+-------------+
| 5       |
| 6       |
+-------------+
Output: 
+-------------+
| customer_id |
+-------------+
| 1       |
| 3       |
+-------------+
Explanation: 
The customers who bought all the products (5 and 6) are customers with IDs 1 and 3.

Solutions

Solution 1: Grouping and Subquery

We can group the Customer table by customer_id, and then use the HAVING clause to filter out the customers who have not purchased all products. To do this, we can use a subquery to find the total number of distinct products, and then compare it with the number of distinct products purchased by each customer.

# Write your MySQL query statement below
SELECT customer_id
FROM Customer
GROUP BY 1
HAVING COUNT(DISTINCT product_key) = (SELECT COUNT(1) FROM Product);

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。
列表为空,暂无数据
    我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
    原文