Question

Debug

输入sql语句，但不执行

debug()

Return: 开启Medoo调试模式

输出sql语句，不需要使用echo或其它方法。调试完成请移除此代码

$database->debug()->select("bccount", [    "user_name",    "email"], [    "user_id[ 20]);// Will output:// SELECT "user_name","email" FROM "bccount" WHERE "user_id" insert("account", [    "user_name" => "foo",    "email" => "foo@bar.com"]);// Will output the generated query$post_id = $database->debug()->get("post", "post_id", ["user_name" => "foo"]);// Be careful, this query will be executed.$database->update("account", [    "level[+]" => 5,    "post" => $post_id], [    "user_name" => "foo"]);