Question

Debug

输入 sql 语句，但不执行

debug()

Return: 开启 Medoo 调试模式

输出 sql 语句，不需要使用 echo 或其它方法。调试完成请移除此代码

$database->debug()->select("bccount", [
    "user_name",
    "email"], [
    "user_id[ 20]);
// Will output:
// SELECT "user_name","email" FROM "bccount" WHERE "user_id" 
insert("account", [
    "user_name" => "foo",
    "email" => "foo@bar.com"]
);
// Will output the generated query
$post_id = $database->debug()->get("post", "post_id", ["user_name" => "foo"]);
// Be careful, this query will be executed.
$database->update("account", [
    "level[+]" => 5,
    "post" => $post_id], [
    "user_name" => "foo"]
);