Question

typedef void * (*lua_Alloc) (void *ud,
 void *ptr,
 size_t osize,
 size_t nsize);

The type of the memory-allocation function used by Lua states. The allocator function must provide a functionality similar to realloc, but not exactly the same. Its arguments are ud, an opaque pointer passed to lua_newstate; ptr, a pointer to the block being allocated/reallocated/freed; osize, the original size of the block; nsize, the new size of the block. ptr is NULL if and only if osize is zero. When nsize is zero, the allocator must return NULL; if osize is not zero, it should free the block pointed to by ptr. When nsize is not zero, the allocator returns NULL if and only if it cannot fill the request. When nsize is not zero and osize is zero, the allocator should behave like malloc. When nsize and osize are not zero, the allocator behaves like realloc. Lua assumes that the allocator never fails when osize >= nsize.

Here is a simple implementation for the allocator function. It is used in the auxiliary library by lua_newstate.

 static void *l_alloc (void *ud, void *ptr, size_t osize, size_t nsize) {
 (void)ud; /* not used */
 (void)osize; /* not used */
 if (nsize == 0) {
 free(ptr); /* ANSI requires that free(NULL) has no effect */
 return NULL;
 }
 else
 /* ANSI requires that realloc(NULL, size) == malloc(size) */
 return realloc(ptr, nsize);
 }