Question

1078. Occurrences After Bigram

中文文档

Description

Given two strings first and second, consider occurrences in some text of the form "first second third", where second comes immediately after first, and third comes immediately after second.

Return _an array of all the words_ third _for each occurrence of_ "first second third".

 

Example 1:

Input: text = "alice is a good girl she is a good student", first = "a", second = "good"
Output: ["girl","student"]

Example 2:

Input: text = "we will we will rock you", first = "we", second = "will"
Output: ["we","rock"]

 

Constraints:

• 1 <= text.length <= 1000
• text consists of lowercase English letters and spaces.
• All the words in text a separated by a single space.
• 1 <= first.length, second.length <= 10
• first and second consist of lowercase English letters.

Solutions

Solution 1

class Solution:
  def findOcurrences(self, text: str, first: str, second: str) -> List[str]:
    words = text.split()
    ans = []
    for i in range(len(words) - 2):
      a, b, c = words[i : i + 3]
      if a == first and b == second:
        ans.append(c)
    return ans

class Solution {

  public String[] findOcurrences(String text, String first, String second) {
    String[] words = text.split(" ");
    List<String> ans = new ArrayList<>();
    for (int i = 0; i < words.length - 2; ++i) {
      if (first.equals(words[i]) && second.equals(words[i + 1])) {
        ans.add(words[i + 2]);
      }
    }
    return ans.toArray(new String[0]);
  }
}

class Solution {
public:
  vector<string> findOcurrences(string text, string first, string second) {
    istringstream is(text);
    vector<string> words;
    string word;
    while (is >> word) {
      words.emplace_back(word);
    }
    vector<string> ans;
    int n = words.size();
    for (int i = 0; i < n - 2; ++i) {
      if (words[i] == first && words[i + 1] == second) {
        ans.emplace_back(words[i + 2]);
      }
    }
    return ans;
  }
};

func findOcurrences(text string, first string, second string) (ans []string) {
  words := strings.Split(text, " ")
  n := len(words)
  for i := 0; i < n-2; i++ {
    if words[i] == first && words[i+1] == second {
      ans = append(ans, words[i+2])
    }
  }
  return
}

function findOcurrences(text: string, first: string, second: string): string[] {
  const words = text.split(' ');
  const n = words.length;
  const ans: string[] = [];
  for (let i = 0; i < n - 2; i++) {
    if (words[i] === first && words[i + 1] === second) {
      ans.push(words[i + 2]);
    }
  }
  return ans;
}