Question

所属分类：回调对象

callbacks.empty()返回: Callbacks

描述: 从列表中删除所有的回调.

• 添加的版本: 1.7callbacks.empty()

  • 这个方法不接受任何参数

此方法返回绑定它的那个回调对象(this).

Example

用callbacks.empty()清空一个回调的列表:

// a sample logging function to be added to a callbacks list
var foo = function( value1, value2 ) {
  console.log( "foo: " + value1 + "," + value2 );
}
 
// another function to also be added to the list
var bar = function( value1, value2 ){
    console.log( "bar: " + value1 + "," + value2 );
}
 
var callbacks = $.Callbacks();
 
// add the two functions
callbacks.add( foo );
callbacks.add( bar );
 
// empty the callbacks list
callbacks.empty();
 
// check to ensure all callbacks have been removed
console.log( callbacks.has( foo ) );
// false
console.log( callbacks.has( bar ) );
// false