Question

181. Employees Earning More Than Their Managers

中文文档

Description

Table: Employee

+-------------+---------+
| Column Name | Type  |
+-------------+---------+
| id      | int   |
| name    | varchar |
| salary    | int   |
| managerId   | int   |
+-------------+---------+
id is the primary key (column with unique values) for this table.
Each row of this table indicates the ID of an employee, their name, salary, and the ID of their manager.

 

Write a solution to find the employees who earn more than their managers.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Employee table:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3     |
| 2  | Henry | 80000  | 4     |
| 3  | Sam   | 60000  | Null    |
| 4  | Max   | 90000  | Null    |
+----+-------+--------+-----------+
Output: 
+----------+
| Employee |
+----------+
| Joe    |
+----------+
Explanation: Joe is the only employee who earns more than his manager.

Solutions

Solution 1

import pandas as pd


def find_employees(employee: pd.DataFrame) -> pd.DataFrame:
  df = employee.merge(right=employee, how="left", left_on="managerId", right_on="id")
  emp = df[df["salary_x"] > df["salary_y"]]["name_x"]

  return pd.DataFrame({"Employee": emp})

SELECT Name AS Employee
FROM Employee AS Curr
WHERE
  Salary > (
    SELECT Salary
    FROM Employee
    WHERE Id = Curr.ManagerId
  );

Solution 2

# Write your MySQL query statement below
SELECT
  e1.name AS Employee
FROM
  Employee AS e1
  JOIN Employee AS e2 ON e1.managerId = e2.id
WHERE e1.salary > e2.salary;