Question

434. Number of Segments in a String

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Description

Given a string s, return _the number of segments in the string_.

A segment is defined to be a contiguous sequence of non-space characters.

 

Example 1:

Input: s = "Hello, my name is John"
Output: 5
Explanation: The five segments are ["Hello,", "my", "name", "is", "John"]

Example 2:

Input: s = "Hello"
Output: 1

 

Constraints:

• 0 <= s.length <= 300
• s consists of lowercase and uppercase English letters, digits, or one of the following characters "!@#$%^&*()_+-=',.:".
• The only space character in s is ' '.

Solutions

Solution 1

class Solution:
  def countSegments(self, s: str) -> int:
    return len(s.split())

class Solution {
  public int countSegments(String s) {
    int ans = 0;
    for (String t : s.split(" ")) {
      if (!"".equals(t)) {
        ++ans;
      }
    }
    return ans;
  }
}

class Solution {
public:
  int countSegments(string s) {
    int ans = 0;
    istringstream ss(s);
    while (ss >> s) ++ans;
    return ans;
  }
};

func countSegments(s string) int {
  ans := 0
  for _, t := range strings.Split(s, " ") {
    if len(t) > 0 {
      ans++
    }
  }
  return ans
}

class Solution {
  /**
   * @param String $s
   * @return Integer
   */
  function countSegments($s) {
    $arr = explode(' ', $s);
    $cnt = 0;
    for ($i = 0; $i < count($arr); $i++) {
      if (strlen($arr[$i]) != 0) {
        $cnt++;
      }
    }
    return $cnt;
  }
}

Solution 2

class Solution:
  def countSegments(self, s: str) -> int:
    ans = 0
    for i, c in enumerate(s):
      if c != ' ' and (i == 0 or s[i - 1] == ' '):
        ans += 1
    return ans

class Solution {
  public int countSegments(String s) {
    int ans = 0;
    for (int i = 0; i < s.length(); ++i) {
      if (s.charAt(i) != ' ' && (i == 0 || s.charAt(i - 1) == ' ')) {
        ++ans;
      }
    }
    return ans;
  }
}

class Solution {
public:
  int countSegments(string s) {
    int ans = 0;
    for (int i = 0; i < s.size(); ++i) {
      if (s[i] != ' ' && (i == 0 || s[i - 1] == ' ')) {
        ++ans;
      }
    }
    return ans;
  }
};

func countSegments(s string) int {
  ans := 0
  for i, c := range s {
    if c != ' ' && (i == 0 || s[i-1] == ' ') {
      ans++
    }
  }
  return ans
}