Question

2169. Count Operations to Obtain Zero

中文文档

Description

You are given two non-negative integers num1 and num2.

In one operation, if num1 >= num2, you must subtract num2 from num1, otherwise subtract num1 from num2.

• For example, if num1 = 5 and num2 = 4, subtract num2 from num1, thus obtaining num1 = 1 and num2 = 4. However, if num1 = 4 and num2 = 5, after one operation, num1 = 4 and num2 = 1.

Return _the number of operations required to make either_ num1 = 0 _or_ num2 = 0.

 

Example 1:

Input: num1 = 2, num2 = 3
Output: 3
Explanation: 
- Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1.
- Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1.
- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1.
Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations.
So the total number of operations required is 3.

Example 2:

Input: num1 = 10, num2 = 10
Output: 1
Explanation: 
- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0.
Now num1 = 0 and num2 = 10. Since num1 == 0, we are done.
So the total number of operations required is 1.

 

Constraints:

• 0 <= num1, num2 <= 105

Solutions

Solution 1

class Solution:
  def countOperations(self, num1: int, num2: int) -> int:
    ans = 0
    while num1 and num2:
      if num1 >= num2:
        num1, num2 = num2, num1
      num2 -= num1
      ans += 1
    return ans

class Solution {
  public int countOperations(int num1, int num2) {
    int ans = 0;
    while (num1 != 0 && num2 != 0) {
      if (num1 >= num2) {
        num1 -= num2;
      } else {
        num2 -= num1;
      }
      ++ans;
    }
    return ans;
  }
}

class Solution {
public:
  int countOperations(int num1, int num2) {
    int ans = 0;
    while (num1 && num2) {
      if (num1 > num2) swap(num1, num2);
      num2 -= num1;
      ++ans;
    }
    return ans;
  }
};

func countOperations(num1 int, num2 int) int {
  ans := 0
  for num1 != 0 && num2 != 0 {
    if num1 > num2 {
      num1, num2 = num2, num1
    }
    num2 -= num1
    ans++
  }
  return ans
}

function countOperations(num1: number, num2: number): number {
  let ans = 0;
  while (num1 && num2) {
    [num1, num2] = [Math.min(num1, num2), Math.abs(num1 - num2)];
    ans++;
  }
  return ans;
}