Question

492. Construct the Rectangle

中文文档

Description

A web developer needs to know how to design a web page's size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

Return _an array [L, W] where L and W are the length and width of the web page you designed in sequence._

 

Example 1:

Input: area = 4
Output: [2,2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Example 2:

Input: area = 37
Output: [37,1]

Example 3:

Input: area = 122122
Output: [427,286]

 

Constraints:

• 1 <= area <= 107

Solutions

Solution 1

class Solution:
  def constructRectangle(self, area: int) -> List[int]:
    w = int(sqrt(area))
    while area % w != 0:
      w -= 1
    return [area // w, w]

class Solution {
  public int[] constructRectangle(int area) {
    int w = (int) Math.sqrt(area);
    while (area % w != 0) {
      --w;
    }
    return new int[] {area / w, w};
  }
}

class Solution {
public:
  vector<int> constructRectangle(int area) {
    int w = sqrt(1.0 * area);
    while (area % w != 0) --w;
    return {area / w, w};
  }
};

func constructRectangle(area int) []int {
  w := int(math.Sqrt(float64(area)))
  for area%w != 0 {
    w--
  }
  return []int{area / w, w}
}