返回介绍

solution / 0500-0599 / 0571.Find Median Given Frequency of Numbers / README_EN

发布于 2024-06-17 01:03:59 字数 2132 浏览 0 评论 0 收藏 0

571. Find Median Given Frequency of Numbers

中文文档

Description

Table: Numbers

+-------------+------+
| Column Name | Type |
+-------------+------+
| num     | int  |
| frequency   | int  |
+-------------+------+
num is the primary key (column with unique values) for this table.
Each row of this table shows the frequency of a number in the database.

 

The median is the value separating the higher half from the lower half of a data sample.

Write a solution to report the median of all the numbers in the database after decompressing the Numbers table. Round the median to one decimal point.

The result format is in the following example.

 

Example 1:

Input: 
Numbers table:
+-----+-----------+
| num | frequency |
+-----+-----------+
| 0   | 7     |
| 1   | 1     |
| 2   | 3     |
| 3   | 1     |
+-----+-----------+
Output: 
+--------+
| median |
+--------+
| 0.0  |
+--------+
Explanation: 
If we decompress the Numbers table, we will get [0, 0, 0, 0, 0, 0, 0, 1, 2, 2, 2, 3], so the median is (0 + 0) / 2 = 0.

Solutions

Solution 1

# Write your MySQL query statement below
WITH
  t AS (
    SELECT
      *,
      SUM(frequency) OVER (ORDER BY num ASC) AS rk1,
      SUM(frequency) OVER (ORDER BY num DESC) AS rk2,
      SUM(frequency) OVER () AS s
    FROM Numbers
  )
SELECT
  ROUND(AVG(num), 1) AS median
FROM t
WHERE rk1 >= s / 2 AND rk2 >= s / 2;

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。
列表为空,暂无数据
    我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
    原文